(2x-1)(2x+2)-(4x+5)^2=-4x-2.... Question from @15karolina

October 2018 2 14 Report

(2x-1)(2x+2)-(4x+5)^2=-4x-2

Roma

$(2x-1)(2x+2)-(4x+5)^2=-4x-2$

$4x^2 + 4x - 2x - 2 - (16x^2 + 40x + 25) + 4x + 2 = 0$

$4x^2 + 4x - 2x - 2 - 16x^2 - 40x - 25 + 4x + 2 = 0$

$-12x^2-34x - 25 = 0$

$a = -12; \ b =-34; \ c = - 25$

$\Delta = b^2 - 4ac = (-34)^2 - 4 \cdot (-12) \cdot (-25) = 1156 - 1200 = - 44<0$

Równanie nie ma rozwiązań.

1 votes Thanks 0

Cheeky

(4x²+4x-2x-2)-(16x²+40x+25)=-4x-2

4x²+2x-2-16x²-40x-25=-4x-2

-12x²-34x-25=0

Δ=(-34)²-4(-12)(-25)

Δ=1156-1200

Δ ujemna, więc nie ma miejsc zerowych, więc brak rozwiązań

1 votes Thanks 0

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