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zadania:
1. (8/2+4*3)/4+(6*2-3*5)*6-36/12=
2. [(2048-4000/2)/8+(512-256)/4]/2=
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1. (8/2+4*3)/4+(6*2-3*5)*6-36/12=(4 + 12)/4 + (12 - 15)*6 - 3 = 16/4 -3*6 - 3 = 4 - 18 -3 = -17
2. [(2048-4000/2)/8+(512-256)/4]/2= [(2048 - 2000)/8 + 256/4]/2 = (48/8+ 64)/2 = (6 +64)/2 = 70/2 = 35
1. (4+12)/4+(12-15)*6-3=16/4+(-3)*6-3=4-18-3=-17
2. [(2048-2000)/8+256/4]/2=[48/8+64]/2=[6+64]/2=70/2=35