Oblicz x:
cos(pi-3x)=1/2
Pomysły tudzież rozwiązania??
Bo moje sie okazują błędne.
π-3x=π/3+2kπ
-3x=π/3+2kπ-π
x=-(π/3+2kπ-π)/3
x=-(-2π/3+2kπ)/3
x=(2π/3-2kπ)/3
x=2π/9-2kπ/3
π-3x=-π/3+2kπ
-3x=-π/3+2kπ-π
x=-(-π/3+2kπ-π)/3
x=-(-4π/3+kπ)/3
x=(4π/3-2kπ)/3
x=4π/9-2kπ/3
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π-3x=π/3+2kπ
-3x=π/3+2kπ-π
x=-(π/3+2kπ-π)/3
x=-(-2π/3+2kπ)/3
x=(2π/3-2kπ)/3
x=2π/9-2kπ/3
π-3x=-π/3+2kπ
-3x=-π/3+2kπ-π
x=-(-π/3+2kπ-π)/3
x=-(-4π/3+kπ)/3
x=(4π/3-2kπ)/3
x=4π/9-2kπ/3