Question

Ciąg geometryczny: Oblicz iloczyn pierwszych 5 wyrazów ciągu geometrycznego danego wzorem an=8/2^n, gdzie n>_1

Answer 1

a1=8/2^1=8/2=4

a2=8/2^2=8/4=2

a3=8/2^3=8/8=1

a4=8/2^4=8/16=1/2

a5=8/a^5=8/32=1/4

a1*a2*a3*a4*a5=4*2*1*1/2*1/4=1

Answer 2

an =8/2^(n)

 

a1 =8/2^1 =8/2 = 4

a2 = 8/2^2 = 8/4 =2

a3 = 8/2^3 = 8/8 =1

a4 = 8/2^4 = 8/16 =1/2

a5 = 8/2^5 = 8/32 =1/4

 

a1*a2*a3*a4*a5 = 4*2*1*1/2*1/4 =8/8 =1