Question

1. 3log2 x 2log6 x 6log9=
2. 1/2log9 x 1/2log7 x 49log32=
3.4log9 x 3log125 x 25log16=
#pakai cara plis

Answer 1

Verified answer

1)3log2×2log6×6log9=
3log 2×2log3.2×3.2log 3pangkat2

2×2=4

Answer 2

1.  a log b . b log c = a log c

     3log2 .  2log6  . 6log9 = 3 log 9
                                         = 3 log 3²
                                        = 2
2.  1/2  log 9 . 1/2 log 7 . 49 log 32 =
      2⁻¹  log 3² .  2⁻¹ log 7  . 7²log 2⁵=
     2/(-1)  .  2 log 3 .  1/(-1) . 2 log 7 . 5/2 . 7 log 2 =
     5 .   2 log 3 . 2 log 7 . 7 log 2 = 5 .  2 log 3

3.  4 log 9  .   3 log 125  . 25 log 16=
     2² log 3² . 3 log 5³ . 5² log 2⁴ =
    2/2 .  2 log 3 .  1/3 . 3 log 5 . 4/2 . 5 log 2 =
    2/3  .  2 log 3 . 3 log 5 . 5 log 2= 2/3