Question

2log 3 = a, 5log 2 =b ,maka 6log 15=

Answer 1

⁶ log 15 = {² log 15} / {² log 6}
⁶ log 15 = {² log 5 + ² log 3} / {²log 2 + ²log 3}
⁶ log 15 = {1/b + a} / {1 + a}
⁶ log 15 = {(1 + ab)/b} / (1 + a)
⁶ log 15 = (ab + 1) / (ab + b)

Answer 2

6log(3.5)= 6log3+6log5=
1/(3log6) + 1/(5log6)=
1/(3log3+3log2) + 1/(5log3+5log2)=
1/(1+1/2log3) + 1/(5log2.2log3+b)=
1/(1+1/a) + 1/(ab+b)=
a/(a+1) + 1/[b(a+1)]=
(ab+1)/[b(a+1)]