Question

2log 3 = a, 5log 2 =b ,ala 6log 15=

Answer 1

6log(3.5)= 6log3+6log5=
1/(3log6) + 1/(5log6)=
1/(3log3+3log2) + 1/(5log3+5log2)=
1/(1+1/2log3) + 1/(5log2.2log3+b)=
1/(1+1/a) + 1/(ab+b)=
a/(a+1) + 1/[b(a+1)]=
(ab+1)/[b(a+1)]