Question

2/3u*...=u -1/2v: ...=1/8v (-4)*(2a-b)= -2(-4b+3)= (a+b)*(-4)= (4-5+6y)*3= -3(3x-2)= -1(3-y+2)= (10x+2y):2= (-3a+12):(-3)= (24a-4b):8= (4u-6v):(-1/2)=

Answer 1

2/3u*3/2=u

-1/2v:(-4/1)=1/8v

(-4)*(2a-b)= -8a+4b

-2(-4b+3)= 8b-6

(a+b)*(-4)= -4a-4b

(4-5+6y)*3= 12-15+18y= -3+18y

-3(3x-2)= -9x+6

-1(3-y+2)= -3+y-2= -5+y

(10x+2y):2= 5x+y

(-3a+12):(-3)= a-4

(24a-4b):8= 3a-2b

(4u-6v):(-1/2)= -8u+12v