Dana jest funkcja określona wzorem :
a) f(x)=2x+1 Oblicz: f(0) , f(-1/2) , f(3/2)
b) g(x)= x^{2} -3 / x-1 Oblicz g(-1) , g(3) . g(1/2)
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a)
f(x) = 2x +1
f(0) = 2 * 0 +1 = 1
f(-1/2) = 2 *(-1/2) +1 = -1+1 = 0
f(3/2) = 2 *3/2 +1 = 3+1 = 4
b)
g(x) = (x^2 -1)/(x-1)
g(-1) = [(-1)^2 -1]/(-1-1) = (1-1)/(-2) = 0
g(3) = (3^2 -1)/(3-1) = (9-1)/2 = 4
g(1/2) = [(1/2)^2 -1]/(1/2 -1) = (1/4 -1)/(1/2 -1) = -3/4 *(-2) = 1,5
a)
b)