Question

2(a do potęgi 3 -b)+(a do potęgi 2 + b do potęgi 2 ) =

Answer 1

2(a³-b)+(a²+b²)=2a³-2b+a²+b²=2a³+a²+b²-2b

 

:)

Answer 2

2(a do potęgi 3 -b)+(a do potęgi 2 + b do potęgi 2 ) =

=2(a³-b)+(a²+b²)=

=2a³-2b+a²+b²=

=2a³+a²+b²-2b

 

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