Question

a)log1/3 1/27

b)log7 pierwiastek z 7

c) log2dodrugiej pierwiastek z 2

d)log pierwiastek z 2 2

Answer 1

a)

log 1/3 [ 1/27] = 3,         bo   (1/3)^3 = 1/27

b)

log 7 [ p(7)] = 1/2 ,         bo   7^(1/2) = p(7)

c)

log 2^2 [ p(2) ] = log 4 [ p(2) ] = 1/4,   bo    4 ^(1/4) = p(2)

d)

log p(2) [ 2 ] = 2,   bo  [ p(2) ]^2 = 2

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Answer 2