√27+2√12-√48 prosze o pomoc z gory wielkie dzieki
√27 + 2√12 - √48 = √(9 * 3) + 2√(4 * 3) - √(16 * 3) = 3√3 + 2 * 2√3 - 4√3 = 3√3 + 4√3 - 4√3 = 3√3
√27 + 2√12 - √48= √ ( 9 ×3) + 2√(4×3)-√(16×3)=
3√3 + 2 × 2√3 - 4√3 =
3√3 + 4√3 - 4√3=3√3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
√27 + 2√12 - √48 = √(9 * 3) + 2√(4 * 3) - √(16 * 3) = 3√3 + 2 * 2√3 - 4√3 = 3√3 + 4√3 - 4√3 = 3√3
√27 + 2√12 - √48= √ ( 9 ×3) + 2√(4×3)-√(16×3)=
3√3 + 2 × 2√3 - 4√3 =
3√3 + 4√3 - 4√3=3√3