Question

Zapisz jak najprościej:
a. 2a (b-3) - 2b (a-3)
b.a(a+b)+a(a+b)+b(a+b)+(b-a)
c.5a(a-2)+2a(a+5)
d.8x(x+y)-2y(y-x)+1/2(6x do potęgi 2+ 8x do potegi2)-2(y do pot 2 +5xy)

DAJE NAJ

Answer 1

a. 2a (b-3) - 2b (a-3)=2ab-6a-2ab+6b= -6a+6b
b.a(a+b)+a(a+b)+b(a+b)+(b-a)=a²+ab+a²+ab+ab+b²+b-a=2a²+3ab+b²-a+b
c.5a(a-2)+2a(a+5)=5a²-10a+2a²+10a=7a²
d.8x(x+y)-2y(y-x)+1/2(6x²+ 8x²)-2(y² +5xy)=8x²+8xy-2y²+2xy+3x²+4x²-2y²-10xy=15x²-4y²

Answer 2

A) 2a ( b - 3 ) - 2b ( a - 3 ) = 2ab - 6a - 2ab + 6b = - 6a + 6b
b) a ( a + b ) + a ( a + b ) + b ( a + b ) + ( b - a ) = a^2 + ab + a^2 + ab + ab + b^2 + b - a = a^4 + 3ab + b^2 + b - a
c) 5a ( a - 2 ) + 2a ( a + 5 ) = 5a^2 - 10a + 2a^2 +10a = 7a^2
d) 8x ( x + y ) - 2y ( y - x ) + 1/2 ( 6x^2 + 8x^2 ) - 2 ( y^2 + 5xy ) =
= 8x^2 + 8xy - 2y^2 + 2xy + 3x^2 + 4x^2 - 2y^2 - 10xy = 15x^2 - 4y^2

Te ^2 , to znaczy do potęgi 2 :) Liczę na naj :)