tg = a / b
a = 3
b = 2
c = √13- liczymy z pitagorasa
sin = a / c
cos = b / c
ctg = b / a
sin = 3 / √13
cos = 2 / √13
ctg = 2 / 3
Powinno być ok :>
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tg = a / b
a = 3
b = 2
c = √13- liczymy z pitagorasa
sin = a / c
cos = b / c
ctg = b / a
sin = 3 / √13
cos = 2 / √13
ctg = 2 / 3
Powinno być ok :>