Przyjżyj się jak Asia i Leszek rozwiązywali to samo równanie
Asia S.
3(2x-1)=12 /:3
2x-1=4 /+1
2x=5
x= 5/2
x=2 i 1/2
Leszek
3(2-1)=12
6x-3=12/+3
6x=15 /:6
x=15/6
x=2 i 1/2
a) rozwiąż podane równania sposebem Asia
2(5x-1)=8
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1/2(4y+6)=3
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-3(x-2)=-9
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b) rozwiąż podane równania sposobem Leszka:
2(5x-1)=8
...................
...................
...................
1/2(4y+6)=3
...................
...................
...................
-3(x-2)=-9
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...................
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Proszę o pomoc !!!
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a) Sposobem Asi...
2(5x - 1) = 8 |:2
5x-1 = 4 |+1
5x = 5 |:5
x = 1
½(4y + 6) = 3 |:1/2
4y+6 = 6 |-6
4y = 0 |:4
y = 0
-3(x - 2) = -9 |:(-3)
x-2 = 3 |+2
x = 5
a) Sposobem Leszka..
2(5x - 1) = 8
10x-2 = 8 |+2
10x = 10 |:10
x = 1
½(4y + 6) = 3
2y+3 = 3 |-3
2y = 0 |:2
y = 0
-3(x - 2) = -9
-3x+6 = -9 |-6
-3x = -15 |:(-3)
x = -5
Proszę :)
Asia :
2(5x-1)=8 /:2
5x-1=4/+1
5x=5
x=5/5
x=1
1/2(4y+6)=3 /: 1/2
4y+6=6/-6
4y=0
y=0/4
y=0
-3(x-2)=-9/:(-3)
x-2=3/+2
x=5
Leszek:
2(5x-1)=8
10x-2=8/+2
10x=10/:10
x=1
1/2(4y+6)=3
2y+3=3/-3
2y=0/:2
y=0
-3(x-2)=-9
-3x+6=-9/-6
-3x=-15/:(-3)
x=5