rozwiąż równanie:
a)sin5x=1/2
b)2sinx=-1
c)sin(2x+1)=
d)cos x/2=
a) sin5x=1/2
x0=1/2=pi/6
5x=pi/6+2kpi v 5x=5/6pi + 2kpi
x= v x=
b) 2sinx=-1
sinx=-1/2
x0=-pi/6
x=- v x=/
c)sin(2x+1)=to co sie rowna
x0=pi/3
2x+1=pi/3+2kpi v 2x+1=2/3pi +2kpi
najpierw przenosisz potem dzilisz
d) x0=pi/4
x= v x=-
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a) sin5x=1/2
x0=1/2=pi/6
5x=pi/6+2kpi v 5x=5/6pi + 2kpi
x=
v x=![\frac{\pi}{6}+\frac{2k\pi}{5} \frac{\pi}{6}+\frac{2k\pi}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B6%7D%2B%5Cfrac%7B2k%5Cpi%7D%7B5%7D)
b) 2sinx=-1
sinx=-1/2
x0=-pi/6
x=-
v x=/![\frac{7\pi}{6}+2k\pi \frac{7\pi}{6}+2k\pi](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Cpi%7D%7B6%7D%2B2k%5Cpi)
c)sin(2x+1)=to co sie rowna
x0=pi/3
2x+1=pi/3+2kpi v 2x+1=2/3pi +2kpi
najpierw przenosisz potem dzilisz
x=
v x=![\frac{\pi}{3}+k\pi+\frac{1}{2} \frac{\pi}{3}+k\pi+\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B3%7D%2Bk%5Cpi%2B%5Cfrac%7B1%7D%7B2%7D)
d) x0=pi/4
x=
v x=-![\frac{\pi}{2}+4k\pi \frac{\pi}{2}+4k\pi](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B2%7D%2B4k%5Cpi)