Question

Oblicz pole rombu o boku a = 25*5 x 125 : 625*2

i wysokości h =[(1/2)*4 x (1/2)*2 x 1/2]:[(1/2)*3]*3

Answer 1

a = 25*5 * 125 / 625 * 2

a = 5^3 * 5^3 / 5^4 * 2

a = 5^(3+3-4) * 2

a = 5^2 * 2

a = 50

 

h =[(1/2)*4 x (1/2)*2 x 1/2]:[(1/2)*3]*3

h = (2 * 1 * 1/2) / (3/2) * 3

h = 1 * 2/3 * 3 = 2

h = 2

 

P = a*h = 50 * 2

P = 100