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(x-3)(x+3)>2(x+2)²-(x-2)²
x²-9> 2(x²+4x+4)-(x²-4x+4)
x²-9>2x²+8x+8-x²+4x-4
x²-9>x²+12x+4
-9>12x+4
-13>12x
x<-13/12
x∈(-∞,-13/12)
Rozwiąż układ
2(x+3)-3(x+y)=8
5x-3y=1
2x+6- 3x-3y=8
5x-3y=1
-x-3y=2
5x-3y=1|*(-1)
-x-3y=2
-5x+3y=-1
__________
-6x=-1
x=1/6
-1/6-3y=2 |*6
-1-18y=12
-18y=13
y=-13/18