wyrażenie pierwiastek (√6+√3)/(√2+1) proszę o pomoc w rozwiązaniu
(√6+√3)/(√2+1)*[(√2-1)/(√2-1)=
2√3-√6+√6-√3=√3
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(√6+√3)/(√2+1)*[(√2-1)/(√2-1)=
2√3-√6+√6-√3=√3