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sin x=2m²-1
2m²-1>1 ∨ 2m²-1< -1
2m²>2 I:2 2m²<0 I:2
m²>1 m²<0
m²-1>0 m<0
(m-1)(m+1)>0
m∈(-∞;-1)u(1;+∞) ∨ m∈(-∞;0)
czyli
m∈(-∞;0)u(1;+∞)