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b)
c)(xᵃ⁺¹-yᵇ⁻²)²=(xᵃ⁺¹)²-2(xᵃ⁺¹)(yᵇ⁻²)+(yᵇ⁻²)²=x²ᵃ⁺²-2xᵃ⁺¹yᵇ⁻²+y²ᵇ⁻⁴
d) (aˣ⁺²+4bˣ⁻¹)²=(aˣ⁺²)²+2(aˣ⁺²)(4bˣ⁻¹)+(4bˣ⁻¹)²=a²ˣ⁺⁴+8aˣ⁺²bˣ⁻¹+4b²ˣ⁻²
Espero que sirva!Saludos!