[ (1i1/2)^2 - 1i3/5 : 1i 1/3) : 21 wiem ze wynik to 1/20 potrzebuje pełne rozwiązanie
[ (1i1/2)^2 - 1i3/5 : 1i 1/3) : 21 = [(3/2)^2 - 8/5 : 4/3 ] 21 =( 9/4 - 6/5 ) : 21 = (45/20 - 24/20) : 21 = 21/20 : 20 = 1/20
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[ (1i1/2)^2 - 1i3/5 : 1i 1/3) : 21 = [(3/2)^2 - 8/5 : 4/3 ] 21 =( 9/4 - 6/5 ) : 21 = (45/20 - 24/20) : 21 = 21/20 : 20 = 1/20