Zad 1 pierwiastek 81/100
pierwiastek 3 całe 1/16
pierwiastek 0,0049
Zad 2 Zamień podane ułamki na %
a) 7/20
b) 4
zad 1
√[81/100]=√[9²/10²]=9/10
√[3 1/16]=√[49/16]=√[7²/4²]=7/4
√[0,0049]=√[(0,07)²]=0,07
----------------
zad 2
a) 7/20 *100%=(7:20)*100%=0,35*100%=35%
b) 4*100%=400% [???]
1) √81/100=9/10 bo(9/10)²=81/100
√3 i 1/16=√49/16=7/4 =1 i3/4
√0,0049=0,07
2) 7/20=35/100=35%
4=4·100%=400%
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zad 1
√[81/100]=√[9²/10²]=9/10
√[3 1/16]=√[49/16]=√[7²/4²]=7/4
√[0,0049]=√[(0,07)²]=0,07
----------------
zad 2
a) 7/20 *100%=(7:20)*100%=0,35*100%=35%
b) 4*100%=400% [???]
1) √81/100=9/10 bo(9/10)²=81/100
√3 i 1/16=√49/16=7/4 =1 i3/4
√0,0049=0,07
2) 7/20=35/100=35%
4=4·100%=400%