Question

Rozwiąż równania :
a)2x - 6 = 3 ( x + 11 )
b) 1/3 (y - 1 ) = 5y
c) w ułamku 6z + 8 / 2 = 4
d) 3x - 1 = 5 x
e ) y - 3 = 9 - y
f) 1/2 z + 6 = z - 1

Answer 1

A)2x - 6 = 3 ( x + 11 )
2x-6 = 3x + 33
x= -39
b) 1/3 (y - 1 ) = 5y
y-1 = 15y
14y= -1
y= 1/14
c) w ułamku 6z + 8 / 2 = 4
6z+8=8
6z=0
z=0
d) 3x - 1 = 5 x
2x=-1
x=-1/2
e ) y - 3 = 9 - y
2y=12
y=6
f) 1/2 z + 6 = z - 1
z+12=2z-2
z=14

Answer 2

A) 2x - 6 = 3x + 33
x = -39
b) 1/3y - 1/3 = 5y
14/3y = -1/3 | * 3
14y = -1 | : 14
y = -1/14
c) 6z + 8 / 2 = 4 | * 2
6z + 8 = 8 | - 8
6z = 0 | : 6
z = 0
d) 3x - 1 = 5x
2x = -1 | : 2
x = -1/2
e) y - 3 = 9 - y
2y = 12 | : 2
y = 6
f) 1/2z + 6 = z - 1
1/2z = 7
z = 14

Answer 3

A) 2x-6=3(x+11)
2x-6=3x+33
-1x=39
x=-39
b)1/3(y-1)=5y
y/3-1/3=5y
-1/3=4 2/3 y
y=-1/14
c)nie wiem o co ci chodzi "w ułamku"
d) 3x-1=5x
-1=2x
x=-o.5
e)y-3=9-y
2y=12
y=6
f)1/2z+6=z-1
7=1/2z
z=14