Question

Rozwiąż równanie w przedziale (-π/2,π/2) :

tg(x+π/3)=tg(π/2-x)

Answer 1

Tg(x +π/3) = tg ( π/2 - x) w przedziale ( -π/2 ; π/2)
x +π/3 = π/2 - x
2x = π/2 -π/3 = [3π - 2π]/6 = π/6
2x = π/6
x = π/12