Question

1.Zapisz w jak najprostrzej postaci : a) -3(2y+⅓)+4y= b) -6(1-0,5u)+3u/2 = (3u/2 to ułamek) c)2(3w-1)-w+2/2= (w+2/2 to ułamek) d) 3(a-2b)-5(b-2a)= 2.Wykonaj dzielenie: a) (6x-2y):2= b) (-3a-1½):2= c) (2,4a-1,6b):0,8= d) (4u-6v):(-½)=

Answer 1

1.
-3(2y+⅓)+4y=-6y-3+4y=-2y-3
-6(1-0,5u)+3u/2 =-6+3u+3u/2(3u/2 to ułamek)
2(3w-1)-w+2/2=6w-2-w=5w-2
3(a-2b)-5(b-2a)=3a-6b-5b+10a=13a-11b
2.
(6x-2y):2=3x-y
(-3a-1½):2=-1,5a-0.75
(2,4a-1,6b):0,8=3a-2b
(4u-6v):(-½)=-2u+3v