(-2)*0,5x=?
(1/5x)*(-2)
1 1/2z:3=?
2/3u * ? = u
-1/2v: ?=1/8v
Pomocy :D
* to razy,a np;1/2 to ułamek :3
(-2) * 0,5x= -1x = -x
(1/5x) * (-2) = -2/5x
1 1/2z:3= 3/2z * 1/3 = 1/2z
? = u : 2u/3
? = u * 3/2u
? = 3/2
? = -1/2v : v/8
? = -v/2 * 8/v
? = -4
(-2) * 0,5x = -x
1/5x * (-2) = -2/5x
3/2x : 3 = 3/2x * 1/3 = 1/2x
2/3u x ? = u (aby 'znikł' ułamek należy pomnożyć przez jego odwrotność)
2/3u * 3/2 = u
-1/2v * (-1/4) = 1/8v (czyli odwracamy)
(-1/2)v : (-4) = 1/8v
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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(-2) * 0,5x= -1x = -x
(1/5x) * (-2) = -2/5x
1 1/2z:3= 3/2z * 1/3 = 1/2z
2/3u * ? = u
? = u : 2u/3
? = u * 3/2u
? = 3/2
-1/2v: ?=1/8v
? = -1/2v : v/8
? = -v/2 * 8/v
? = -4
(-2) * 0,5x = -x
1/5x * (-2) = -2/5x
3/2x : 3 = 3/2x * 1/3 = 1/2x
2/3u x ? = u (aby 'znikł' ułamek należy pomnożyć przez jego odwrotność)
2/3u * 3/2 = u
-1/2v * (-1/4) = 1/8v (czyli odwracamy)
(-1/2)v : (-4) = 1/8v
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)