Question

Dari tadi ngga ada yang bisa jawab!
jika 1/x+1 + 1/(x+1)^2 + 1/(x+1)^3 + ......
=1/2 tentukan suku kelimanya ! terimakasih

Answer 1

Rasio = 1/(x+1)
S tak hingga = a/(1-r)
1/2 = (1/(x+1))/(1- 1/(x+1))
1/2 = (1/(x+1))/((x+1-1)/(x+1))
1/2 = 1/x
x = 2

U5 = a.r^4
= 1/3. (1/3)^4
= 1/(3)^5