Question

Jika f(x)=2x-3 dan g(x)=1/3x+1 maka (gof)^-1(x-1/2)= ( pake cara :) )

Answer 1

F(x) = 2x-3
g(x)=1/3x+1
(gof)^-1(x-1/2)=y
g(f(x-1/2)=y
g[f(x) -f(1/2)=y
g[(2x-3)-(1-3)=y
g(2x-3-1+3)=y
g(2x-1)=y
1/3(2x-1) + 1=y
2/3x=y
x=2/3y
jadi, (gof)^-1(x-1/2)=2/3y

silahkan dikoreksi kembali :)