Question

Sederhanakan!
a) 1/2× 2^log16 - 1/3×2^log8

b) 2^log akar6 - 2^log 3^1/2

Pake cara ya :)

Answer 1

A) 1/2 . ^2 log 16 - 1/3 . ^2 log 8
= 1/2 . ^2 log 2^4 - 1/3 . ^2 log 2^3
= 1/2 . 4 . ^2 log 2 - 1/3 . 3 . ^2 log 2
= 2 . 1 - 1 . 1
= 2 - 1
= 1


b) ^2 log √6 - ^2 log 3^1/2
= ^2 log √6 - ^2 log √3
= ^2 log (√6 / √3)
= ^2 log √2
= ^2 log 2^1/2
= 1/2 . ^2 log 2
= 1/2 . 1
= 1/2