Zad 6 oblicz a) 4^2 *(1/2)^2 - (1/3)^3 *5^3 b) (1/7)^2 * 14^2 -10^5 * (1/5)^5 c) 35^2 : (-7)^2 + (-6)^3 :(-2)^3 ^ - oznacz potęge np 1/2 -oznacza ulamek 1 do 2
Jackie14
A) (4*(1/2))^2 - ((1/3)*5)^3= 2^2- 1 2/3^3= 4-5= -1 b) ((1/7)*14)^2- (10*(1/5))^5=2^2-2^5= 4-32= -28 c) (35:(-7))^2+ ((-6):(-2))^3=(-5)^2+3^3=25+27=52 Liczę na naj :)
b) ((1/7)*14)^2- (10*(1/5))^5=2^2-2^5= 4-32= -28
c) (35:(-7))^2+ ((-6):(-2))^3=(-5)^2+3^3=25+27=52
Liczę na naj :)