September 2018 1 17 Report

\sqrt[3]{4} \cdot \sqrt[3]{16}=

\sqrt{64}{x^2}{y^6}{z^4}=

2. oblicz wartosc wyrazenia:

\sqrt{2x}\cdot \sqrt{8x} + \sqrt[3]{4x}\cdot \sqrt[3]{2x} +( \sqrt{10x}^{2} )

3. wylacz czynnik przed znak pierwiastka

\sqrt[3]{40}

\sqrt{147}


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.