wiedząc że sin alfa + cos alfa = 7/2 oblicz sin alfa razy cos alfa
sinα+cos²=7/2 ²
sin²α+2sinαcosα+cos²α=49/4
sin²α+cos²α=1
czyli;
1+2sinαcosα=49/4
2sinαcosα=49/4-1
2sinαcosα=49/4-4/4
2sinαcosα=45/4
sinαcosα=45/4:2
sinαcosα=45/8=5,625
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sinα+cos²=7/2 ²
sin²α+2sinαcosα+cos²α=49/4
sin²α+cos²α=1
czyli;
1+2sinαcosα=49/4
2sinαcosα=49/4-1
2sinαcosα=49/4-4/4
2sinαcosα=45/4
sinαcosα=45/4:2
sinαcosα=45/8=5,625