Question

Oblicz entalpie reakcji:
N2(g) + 1/2 O2(g) ----> N2o(g)

C(s) + 2 N2O(g) ---> CO2(g) + 2N2(g) ΔH= -557kJ
C(s) + O2(g) ---> CO2(g) ΔH= -394kJ

Answer 1

1) N2(g)+ 1/2 CO2(g)= 1/2 C(s) + N2O(g) ΔH1= 278,5 kJ/mol
2) C(s)+ O2(g)= CO2(g) ΔH2=-394kJ/mol

ΔHx=278,5 +(-394)= -115,5[kJ/mol]