Proszę o pomoc tg alfa =1/2 (mam problem z początkiem)
tgα = 1/2
tgα = sinα/cosα
1/2 = sinα/cosα (z proprocji) cosα = 2sinα
sin²α + cos²α = 1
cosα = 2sinα
sin²α + (2sinα)² = 1
sin²α + 4sin²α = 1
5sin²α = 1
sin²α = 1/5
sinα = √5/5 lub sinα = -√5/5
cosα = 2√55/ lub cosα = -2√5/5
ctgα = 1/tgα
ctgα = 1/1/2 = 2
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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tgα = 1/2
tgα = sinα/cosα
1/2 = sinα/cosα (z proprocji) cosα = 2sinα
sin²α + cos²α = 1
cosα = 2sinα
sin²α + (2sinα)² = 1
sin²α + 4sin²α = 1
5sin²α = 1
sin²α = 1/5
sinα = √5/5 lub sinα = -√5/5
cosα = 2√55/ lub cosα = -2√5/5
ctgα = 1/tgα
ctgα = 1/1/2 = 2
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)