Hallar el dominio de la función: f(x) = tan(x + 1)
Claves:
1. = [-1, 1] ∪ [2, +∞]
2. = [1, -1]
3. = R - {π/2 + kπ - 1}
4. = R - {1, -1}
5. = [-∞, 0] ∪ [3,+∞]
Claves:
1. = [-1, 1] ∪ [2, +∞]
2. = [1, -1]
3. = R - {π/2 + kπ - 1}
4. = R - {1, -1}
5. = [-∞, 0] ∪ [3,+∞]
More Questions From This User See All
Ésos son de la forma (2 k + a) π/2; también (2 k - 1) π/2
Adoptamos la primera forma.
Por lo tanto x + 1 ≠ (2 k + 1) π/2 ≠ k π + π/2
Finamente x ≠ π/2 + k π - 1, opción 3)
Saludos Herminio