Question

siemka pomuzcie plis

a)4(z+5)=

b)7(y=x-4)= c) 5(4y-2)= d) (3-6a)x8 e)(-2)x(5k+2)=

f) (-4)x(2y-7)= g) -3x(-10-2z)= h( (6-12a )x(-1 /2 )=

i) 2( 8y+5y+1 )= j) 0,1 (-20x+4y)= k ) -1,5(3x-2)

dzęki jak co

Answer 1

a)4(z+5)=4z+20

         

 b)7(y+x-4)=7y + 7x - 28

 

c) 5(4y-2)=20y-10

 

d)  (3-6a)x8= 24 -48a

 

e)(-2)x(5k+2)=-10k - 4

 

f) (-4)x(2y-7)=-8y + 28

 

g) -3x(-10-2z)= 30 + 6z

 

h( (6-12a )x(-1 /2 )=-3 + 6a

 

i) 2( 8y+5y+1 )= 16y+10y+2=26y+2

 

j) 0,1 (-20x+4y)=-2x+0,4y

 

k ) -1,5(3x-2)=-4,5x+3     

Answer 2

a) 4z+20

b)7y+7x-28

c) 20y-10

d)24- 48a

e)-10k-4

f) -8y+28

g) 30+6z

h) -3+6a

i)16y+10y+2=26y+2 

j)-2x+0,4x)

k) -4,5x+3