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Verified answer
Verified answer
∫ x^5 (2 - x^3)^1/2 dx= ∫ x^2 . x^3 (1 - x^3)^1/2 dx
Misal
u = x^3
du = 3x^2 dx
dx = du/(3x^2)
= ∫ x^2 . u . (1 - u)^1/2 du/(3x^2)
= ∫ 1/3 u (1 - u)^1/2 du
Gunakan integral parsial dengan cara tabel
Turunan ... Integral
(+) 1/3 u ....... (1 - u)^1/2
(-) 1/3 .......... -2/3 (1 - u)^3/2
(+) 0 ............ -2/3 . -2/5 (1 - u)^5/2
= 1/3 u (-2/3 (1 - u)^3/2 - 1/3 (-2/3 . -1/5 (1 - u)^5/2) + C
= -2/9 u (1 - u)^3/2 - 2/45 (1 - u)^5/2 + C
= -2/9 x^3 (1 - x^3)^3/2 - 2/45 (1 - x^3)^5/2 + C
= -2/9 x^3 (1 - x^3) √(1 - x^3) - 2/45 (1 - x^3)^2 √(1 - x^3) + C
^ = pangkat