Dam naj !!!
Zad.1oblicz (potegi)
a) (-1/2) do 2 *[(-7,5) do 0 + 4 do 2=
b) (0,3) do 2 : 0.1 do 2 - 0,2 do 3 * (2i 1/2) do 2=
zad.2
przedstaw liczbe w postaci iloczynu poteg liczb pierwszych.
132300:2 prosze tak mi rozwiazac to rownanie az do 1
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a) (-1/2) do 2 *[(-7,5) do 0 + 4 do 2= -1/4*1+16= -1/4 +16 = - 16/4 = -4
b) (0,3) do 2 : 0.1 do 2 - 0,2 do 3 * (2i 1/2) do 2= 0.09:0.01-0.008*5/4 do 2= 9-0.008*25/16=9-8/1000*25/16=9-1/8=1
a)1/20
b)8.9875
zad 2
2do potegi 8 i 3 do potegi 3