" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
f=5 [cm] dl.przekatnych rombu
P=(1/2)ef pole powierzchni rombu
P=(1/2)*7*5 [cm²]
P=(1/2)*35 [cm²]
P=17,5 [cm²]
----------------------------
e=12 [cm]
f=1/2 [dm]=5 [cm]
P=(1/2)*12*5 [cm²]
P=6*5 [cm²]
P=30 [cm²]
--------------------------
e=1,6 [dm]
f=4 [dm]
P=(1/2)*1,6*4 [dm²]
P=2*1,6 [dm²]
P=3,2 [dm²]
a)
7*5/2=35/2=17,5 cm²
b)
1dm=10cm
1/2*10=10/2=5
1/2 dm ma 5 cm
12*5/2=60/2=30 cm²
c)
1,6*10=16cm
4*10=40cm
16*40/2=640/2=320cm²
320/10=32 dm²