Question

Rozwiąż równość
sin4x=-1
sin(2x+π/3)=√3/2
cos(3x-π/4)=√2/2
cos²x+3cosx+2=0

Answer 1

Wszędzie k∈C

sin4x=-1
sin4x=sin(3/2π)
4x=3/2π+2kπ
x=3/8π+k/2π

sin(2x+π/3)=√3/2
sin(2x+π/3)=sin(π/3)
2x+π/3=π/3+2kπ ∨ 2x+π/3=2/3π+2kπ
x=kπ ∨ x=π/6+kπ

cos(3x-π/4)=√2/2
cos(3x-π/4)=cos(π/4)
3x-π/4=π/4+2kπ ∨ 3x-π/4=-π/4+2kπ
x=π/6+2/3kπ ∨ x=2/3kπ

cos²x+3cosx+2=0
(cosx+2)(cosx+1)=0
cosx=-2 ∨ cosx=-1
bzdura x=cos(π)
x=π+2kπ