Question

Rozwiąż równania:

2x-6=3(x+1)

1/3 [jedna trzecia](y-1)=5y

6z+8 / 2 = 4 Pliss

Answer 1

2x-6=3(x+1)
2x-6=3x+3
-x=9
x=-9

1/3(y-1)=5y |*3
y-1=15y
-14y=1
y=-1/14

6z+8/2=4 |*2
12z+8=8
12z=0
z=0

Answer 2

2x-6=3(x+1)
2x-6=3x+3
2x-3x=3+6
-x=9
x=-9


1/3(y-1)=5y
⅓y-⅓=5y
⅓y-5y=⅓
-4⅔y=⅓
y=-¹/₁₄


6z+8 / 2 = 4
3z+4=4
3z=4-4
3z=0
x=0

Answer 3

2x-6=3(x+1)
2x-6=3x+3
2x-3x=3+6
-x=9
x=-9


1/3(y-1)=5y
⅓y-⅓=5y
⅓y-5y=⅓
-4⅔y=⅓
y=-¹/₁₄


6z+8 / 2 = 4
3z+4=4
3z=4-4
3z=0
x=0