rozwiąż zadanie
22 : (2-1/6) * 3/11 - (7-12) * 3/10
(7- 5do potęgi 0) : 3 ² + 2 ³ * 3/ 4-13
5.5 - [1.2 * 7/12 - 0.8/ -2 ² ] : (-3) dopotęgi -1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
22÷(2-¹/₆)·³/₁₁₋(7-12)·³/₁₀=
22÷(¹²/₆-¹/₆)·³/₁₁+5·³/₁₀=
22÷¹¹/₆·³/₁₁+⁵/₁·³/₁₀= tu ułamki beda sie skracac na krzyz
22÷(¹/₂ +³/₂)=
²²/₁÷⁴/₂=²²/₁·²/₄=²²/₂=11
(7-5)⁰÷3²+2³+³/₄-13=2⁰÷9+8+¾-13=(1÷9)+8+¾-13=¹/₉+8+¾-13=1+²⁷/₃₆+²⁷/₃₆-13=4⁵⁴/₃₆=4½
5,5-[(¹²/₁·⁷/₁₂)-(0,8÷(-2)²]÷(-3)⁻¹=
5,5-[7-(⁸/₁₀÷4]÷(-¹/₃)¹=
5,5-[7-(⁸/₁₀·¼)]÷(-¹/₃)=
5,5-[7-⅕]÷(-¹/₃)=
⁵⁵/₁₀-[³⁵/₅-⅕]÷(-⅓)=
⁵⁵/₁₀-³⁴/₅÷(-⅓)=⁵⁵/₁₀-⁶⁸/₁₀÷(-⅓)=-¹³/₁₀·(-³/₁)=³⁹/₁₀=3⁹/₁₀
mam nadzieje ze pomogłam