Proszę o rozwiązanie układów równań metodą podstawiania:
a) 2x - 5 (y + 1) = - 5
- x + 2(y + 2) = 4
b) 2 y - (3 + y) = 0
- x + y/2 = 2
c) 3x + y = 4
6x - (1 - 2y) = 8
d) ⅙x + 3y = - 20
⅓x - 2y = 16
e) √2x + y = 3
2y - x = 6
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) 2x - 5 (y + 1) = - 5
- x + 2(y + 2) = 4
2x-5y-5=-5
-x+2y+4=4
2x-5y=0
-x+2y=0
2x=-5y/:2
-x+2y=0
x=2,5y
-2,5y+2y=0
x=2,5y
0,,5y=0/:0,5
x=2,5y
y=0
x=2,5*0
y=0
x=0
y=0
e) √2x + y = 3
2y - x = 6
x+y=3
2y-x=6
y=3+x
2y-x=6
y=3+x
2(3+x)-x=6
y=3+x
6+2x-x=6
y=3+x
6+x=6
y=3+x
x=0
y=3+0
x=0
y=3
x=0
c)3x + y = 4
6x - (1 - 2y) =8
3x + y = 4
6x-1+2y=8
3x + y = 4
6x+2y=8+1
3x + y = 4
6x+2y=9
y=4-3x
6x+2y=9
y=4-3x
6x+2(4-3x)=9
6x+8-6x=9
y=4-3x
6x-6x=1
y=4-3x
x=1
y=4-3
x=1
y=1