Question

[2²-√2¼×(-1⅓)²]÷(-⅓)³

Answer 1

[2²-√2¼×(-1⅓)²]÷(-⅓)³=

[4-√9/4×(-4/3)²]÷(-1/27)=

[4-3/2×16/9]*(-27)=

[5/2×16/9]*(-27)=

[5×8/9]*(-27)=

[40/9]*(-27)=

[40]*(-3)=-120

Answer 2

13+4√2
______ ÷1/27≈168
3

Answer 3

[2²-√2¼×(-1⅓)²]÷(-⅓)³
[4-pierwiastek z 9/4x (-4/3) do potęgi 2] +(-1/27)
[4-3/2x*16/9]+(-1/27)
[4-8/3]+(-1/27)
3 i 5/3 -1/27
3 i 45/27-1/27
3i44/27