√6 + √3 / √2 + 1 ?
√6+√3 /*(√2-1) √12-√6+√6-√3 √12-√3
____________ = ______________= ___________=2√3-√3=√3
√2+1 /*(√2-1) 2-√2+√2-1 2-1
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√6+√3 /*(√2-1) √12-√6+√6-√3 √12-√3
____________ = ______________= ___________=2√3-√3=√3
√2+1 /*(√2-1) 2-√2+√2-1 2-1