√10(√40+√22,5) per ⁵√(49)pangkat 5/2 × 10³ ×√0,000036
tolong ya :)
tolong ya :)
Avicennaa
![\frac{ \sqrt{10} ( \sqrt{40} + \sqrt{22,5} )}{ \sqrt[5]{ 7^2{ \frac{5}{2} } } x10^3x \sqrt{0,000036} }](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Csqrt%7B10%7D+%28+%5Csqrt%7B40%7D+%2B+%5Csqrt%7B22%2C5%7D+%29%7D%7B+%5Csqrt%5B5%5D%7B+7%5E2%7B+%5Cfrac%7B5%7D%7B2%7D+%7D+%7D+x10%5E3x+%5Csqrt%7B0%2C000036%7D+%7D+ "\frac{ \sqrt{10} ( \sqrt{40} + \sqrt{22,5} )}{ \sqrt[5]{ 7^2{ \frac{5}{2} } } x10^3x \sqrt{0,000036} }")
0 votes
Thanks 1
giovahart
bro bukanya akar 49 pangkat 5/2 itu sama kaya akar 49
Avicennaa
oiya bener....bentar koreki dulu...