1.Znajdź x : 2, x^2 +3 , x+ 10. prosze o rozwiazania zadania .:)
2 , x² + 3, x + 10
a1 a2 a3
a2 - a1 = a3 - a2
x² + 3 - 2 = x + 10 - x² - 3
x² + 1 = -x² + x + 7
x² + x² - x - 7 + 1 = 0
2x² - x - 6 = 0
Δ = 1 + 24 = 25
√Δ = 5
x1 = (1 - 5) / 4 = -4/4 = -1
x2 = (1 + 5) / 4 = 5/4
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2 , x² + 3, x + 10
a1 a2 a3
a2 - a1 = a3 - a2
x² + 3 - 2 = x + 10 - x² - 3
x² + 1 = -x² + x + 7
x² + x² - x - 7 + 1 = 0
2x² - x - 6 = 0
Δ = 1 + 24 = 25
√Δ = 5
x1 = (1 - 5) / 4 = -4/4 = -1
x2 = (1 + 5) / 4 = 5/4