1.wyznacz a i b w wielomianie W(x)=x3-ax2+bx wiedzac, ze W(1)=0 oraz W (-1)=-32
W(1)=1-a+b=0
W(-1)=-1-a-b=-32
-a+b=-1
-a-b=-31
------------- +
-2a=-32/:(-2)
a=16
-16+b=-1
b=-1+16=15
Odp. a=16, b=15
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W(1)=1-a+b=0
W(-1)=-1-a-b=-32
-a+b=-1
-a-b=-31
------------- +
-2a=-32/:(-2)
a=16
-16+b=-1
b=-1+16=15
Odp. a=16, b=15