BagasNugroho
1. a. tk=5/5 tc + 273= (5/5 x 0) + 273= 273 derajat K b. tc=5/5 tk - 273= (5/5 x 0) - 273=(-273) derajat C c. tc=5/5 tk - 273=(5/5 x 273) - 273= 0 derajat C 2. a. tk=5/5 tc + 273= (5/5 x 27) + 273= 300 derajat C b. tk=5/5 tc + 273= (5/5 x 560) + 273= 833 derajat C c. tk=5/5 tc + 273= (5/5 x (-184)) + 273= 89 derajat C d. tk=5/5 tc + 273= (5/5 x (-300)) + 273= (-27) derajat C
b. tc=5/5 tk - 273= (5/5 x 0) - 273=(-273) derajat C
c. tc=5/5 tk - 273=(5/5 x 273) - 273= 0 derajat C
2. a. tk=5/5 tc + 273= (5/5 x 27) + 273= 300 derajat C
b. tk=5/5 tc + 273= (5/5 x 560) + 273= 833 derajat C
c. tk=5/5 tc + 273= (5/5 x (-184)) + 273= 89 derajat C
d. tk=5/5 tc + 273= (5/5 x (-300)) + 273= (-27) derajat C